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2x^2-7.5x+7=0
a = 2; b = -7.5; c = +7;
Δ = b2-4ac
Δ = -7.52-4·2·7
Δ = 0.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7.5)-\sqrt{0.25}}{2*2}=\frac{7.5-\sqrt{0.25}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7.5)+\sqrt{0.25}}{2*2}=\frac{7.5+\sqrt{0.25}}{4} $
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